यदि (f(x)=\frac{x+1}{x-1}) और (g(x)=\frac{x-1}{x+1}) हैं, तो ((f+g)(0)) का मान क्या है?

If (f(x)=\frac{x+1}{x-1}) and (g(x)=\frac{x-1}{x+1}), what is the value of ((f+g)(0))?

Explanation opens after your attempt
Correct Answer

A. (-2)

Step 1

Concept

(f(0)=\frac{1}{-1}=-1) and (g(0)=\frac{-1}{1}=-1), so the sum is (-2). First check whether the given (x) lies in the domain.

Step 2

Why this answer is correct

The correct answer is A. (-2). (f(0)=\frac{1}{-1}=-1) and (g(0)=\frac{-1}{1}=-1), so the sum is (-2). First check whether the given (x) lies in the domain.

Step 3

Exam Tip

(f(0)=\frac{1}{-1}=-1) और (g(0)=\frac{-1}{1}=-1), इसलिए योग (-2) है। पहले जाँचें कि दिया गया (x) प्रांत में है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x+1}{x-1}) और (g(x)=\frac{x-1}{x+1}) हैं, तो ((f+g)(0)) का मान क्या है? / If (f(x)=\frac{x+1}{x-1}) and (g(x)=\frac{x-1}{x+1}), what is the value of ((f+g)(0))?

Correct Answer: A. (-2). Explanation: (f(0)=\frac{1}{-1}=-1) और (g(0)=\frac{-1}{1}=-1), इसलिए योग (-2) है। पहले जाँचें कि दिया गया (x) प्रांत में है। / (f(0)=\frac{1}{-1}=-1) and (g(0)=\frac{-1}{1}=-1), so the sum is (-2). First check whether the given (x) lies in the domain.

Which concept should I revise for this Mathematics MCQ?

(f(0)=\frac{1}{-1}=-1) and (g(0)=\frac{-1}{1}=-1), so the sum is (-2). First check whether the given (x) lies in the domain.

What exam hint can help solve this Mathematics question?

(f(0)=\frac{1}{-1}=-1) और (g(0)=\frac{-1}{1}=-1), इसलिए योग (-2) है। पहले जाँचें कि दिया गया (x) प्रांत में है।