यदि (f(x)=\frac{x-1}{x+1}) और (g(x)=\frac{x+1}{x-1}) हों, तो ((f-g)(x)) का सरल रूप क्या है?

If (f(x)=\frac{x-1}{x+1}) and (g(x)=\frac{x+1}{x-1}), what is the simplified form of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\frac{-4x}{x^2-1},\ x\ne \pm1\)

Step 1

Concept

The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.

Step 2

Why this answer is correct

The correct answer is A. \(\frac{-4x}{x^2-1},\ x\ne \pm1\). The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.

Step 3

Exam Tip

अंश ((x-1)2-(x+1)2=-4x) है। ऋण चिह्न और वर्ग विस्तार ध्यान से करें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{x-1}{x+1}) और (g(x)=\frac{x+1}{x-1}) हों, तो ((f-g)(x)) का सरल रूप क्या है? / If (f(x)=\frac{x-1}{x+1}) and (g(x)=\frac{x+1}{x-1}), what is the simplified form of ((f-g)(x))?

Correct Answer: A. \(\frac{-4x}{x^2-1},\ x\ne \pm1\). Explanation: अंश ((x-1)2-(x+1)2=-4x) है। ऋण चिह्न और वर्ग विस्तार ध्यान से करें। / The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.

Which concept should I revise for this Mathematics MCQ?

The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.

What exam hint can help solve this Mathematics question?

अंश ((x-1)2-(x+1)2=-4x) है। ऋण चिह्न और वर्ग विस्तार ध्यान से करें।