यदि (f(x)=\frac{2}{x+3}) और (g(x)=\frac{1}{x-1}) हों, तो ((f+g)(x)) का domain क्या होगा?

If (f(x)=\frac{2}{x+3}) and (g(x)=\frac{1}{x-1}), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-3,1}\)

Step 1

Concept

Both denominators must be non-zero, so \(x\neq -3\) and \(x\neq 1\). For rational functions, check all denominators.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-3,1}\). Both denominators must be non-zero, so \(x\neq -3\) and \(x\neq 1\). For rational functions, check all denominators.

Step 3

Exam Tip

दोनों denominators non-zero होने चाहिए, इसलिए \(x\neq -3\) और \(x\neq 1\)। rational functions में सभी denominators check करें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{2}{x+3}) और (g(x)=\frac{1}{x-1}) हों, तो ((f+g)(x)) का domain क्या होगा? / If (f(x)=\frac{2}{x+3}) and (g(x)=\frac{1}{x-1}), what is the domain of ((f+g)(x))?

Correct Answer: A. \(\mathbb{R}-{-3,1}\). Explanation: दोनों denominators non-zero होने चाहिए, इसलिए \(x\neq -3\) और \(x\neq 1\)। rational functions में सभी denominators check करें। / Both denominators must be non-zero, so \(x\neq -3\) and \(x\neq 1\). For rational functions, check all denominators.

Which concept should I revise for this Mathematics MCQ?

Both denominators must be non-zero, so \(x\neq -3\) and \(x\neq 1\). For rational functions, check all denominators.

What exam hint can help solve this Mathematics question?

दोनों denominators non-zero होने चाहिए, इसलिए \(x\neq -3\) और \(x\neq 1\)। rational functions में सभी denominators check करें।