यदि (f(x)=\frac{1}{x+2}) और डोमेन ([-6,-3]) है, तो रेंज क्या होगी?
If (f(x)=\frac{1}{x+2}) and the domain is ([-6,-3]), what is the range?
Explanation opens after your attempt
Correct Answer
A. \([-1,-\frac{1}{4}]\)
Concept
The value of (x+2) lies in ([-4,-1]), so the reciprocal gives \([-1,-\frac{1}{4}]\). In exams handle the order carefully for negative denominators.
Why this answer is correct
The correct answer is A. \([-1,-\frac{1}{4}]\). The value of (x+2) lies in ([-4,-1]), so the reciprocal gives \([-1,-\frac{1}{4}]\). In exams handle the order carefully for negative denominators.
Exam Tip
(x+2) की वैल्यू ([-4,-1]) में है, इसलिए reciprocal \([-1,-\frac{1}{4}]\) देता है। परीक्षा में ऋणात्मक denominator पर क्रम सावधानी से रखें।
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