यदि (f(x)=\frac{1}{x-2}) और (g(x)=x+4) हों, तो ((f+g)(x)) का domain क्या होगा?
If (f(x)=\frac{1}{x-2}) and (g(x)=x+4), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{2}\)
Concept
In (f(x)), the denominator (x-2) cannot be zero, so \(x\neq 2\). The polynomial (g(x)) is defined for all real (x).
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{2}\). In (f(x)), the denominator (x-2) cannot be zero, so \(x\neq 2\). The polynomial (g(x)) is defined for all real (x).
Exam Tip
(f(x)) में denominator (x-2) शून्य नहीं हो सकता, इसलिए \(x\neq 2\)। polynomial (g(x)) सभी real (x) पर defined है।
Login to save your score, XP, coins and progress.