यदि (f(x)=\frac{1}{x-2}) और (g(x)=\sqrt{x+3}) हों, तो ((fg)(x)) का प्रांत क्या होगा?

If (f(x)=\frac{1}{x-2}) and (g(x)=\sqrt{x+3}), what is the domain of ((fg)(x))?

Explanation opens after your attempt
Correct Answer

A. \( [-3,\infty\)\setminus{2} )

Step 1

Concept

The root needs \(x\ge -3\) and the denominator needs \(x\ne 2\). For a product, take the common domain of both functions.

Step 2

Why this answer is correct

The correct answer is A. \( [-3,\infty\)\setminus{2} ). The root needs \(x\ge -3\) and the denominator needs \(x\ne 2\). For a product, take the common domain of both functions.

Step 3

Exam Tip

मूल के लिए \(x\ge -3\) और हर के लिए \(x\ne 2\) चाहिए। गुणन में भी दोनों फलनों का सामान्य प्रांत लिया जाता है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{x-2}) और (g(x)=\sqrt{x+3}) हों, तो ((fg)(x)) का प्रांत क्या होगा? / If (f(x)=\frac{1}{x-2}) and (g(x)=\sqrt{x+3}), what is the domain of ((fg)(x))?

Correct Answer: A. \( [-3,\infty\)\setminus{2} ). Explanation: मूल के लिए \(x\ge -3\) और हर के लिए \(x\ne 2\) चाहिए। गुणन में भी दोनों फलनों का सामान्य प्रांत लिया जाता है। / The root needs \(x\ge -3\) and the denominator needs \(x\ne 2\). For a product, take the common domain of both functions.

Which concept should I revise for this Mathematics MCQ?

The root needs \(x\ge -3\) and the denominator needs \(x\ne 2\). For a product, take the common domain of both functions.

What exam hint can help solve this Mathematics question?

मूल के लिए \(x\ge -3\) और हर के लिए \(x\ne 2\) चाहिए। गुणन में भी दोनों फलनों का सामान्य प्रांत लिया जाता है।