यदि (f(x)=\frac{1}{x-1}) और डोमेन ([3,9]) है, तो रेंज क्या होगी?
If (f(x)=\frac{1}{x-1}) and the domain is ([3,9]), what is the range?
Explanation opens after your attempt
A. \([\frac{1}{8},\frac{1}{2}]\)
Concept
On this domain the denominator is positive and the reciprocal decreases. (x=3) gives \(\frac{1}{2}\) and (x=9) gives \(\frac{1}{8}\).
Why this answer is correct
The correct answer is A. \([\frac{1}{8},\frac{1}{2}]\). On this domain the denominator is positive and the reciprocal decreases. (x=3) gives \(\frac{1}{2}\) and (x=9) gives \(\frac{1}{8}\).
Exam Tip
इस domain पर denominator धनात्मक है और reciprocal घटता है। (x=3) से \(\frac{1}{2}\) और (x=9) से \(\frac{1}{8}\) मिलता है।
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