यदि (f(x)=\frac{1}{x-1}) और (g(x)=\frac{1}{x+2}) हों, तो ((f+g)(x)) का डोमेन क्या है?
If (f(x)=\frac{1}{x-1}) and (g(x)=\frac{1}{x+2}), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\mathbb{R}-{-2,1}\)
Concept
The denominators require \(x-1\ne 0\) and \(x+2\ne 0\), so \(x\ne 1,-2\). For addition, use the common domain of both functions.
Why this answer is correct
The correct answer is A. \(\mathbb{R}-{-2,1}\). The denominators require \(x-1\ne 0\) and \(x+2\ne 0\), so \(x\ne 1,-2\). For addition, use the common domain of both functions.
Exam Tip
हर में \(x-1\ne 0\) और \(x+2\ne 0\), इसलिए \(x\ne 1,-2\)। जोड़ के लिए दोनों फलनों का साझा डोमेन लें।
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