यदि (f(x)=\frac{1}{x-1}) और (g(x)=\frac{1}{x+1}) हैं, तो ((f-g)(x)) क्या है?
If (f(x)=\frac{1}{x-1}) and (g(x)=\frac{1}{x+1}), what is ((f-g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\frac{2}{x^2-1}\)
Concept
(\frac{1}{x-1}-\frac{1}{x+1}=\frac{x+1-(x-1)}{x-2-1}=\frac{2}{x-2-1}). Watch numerator signs while taking a common denominator.
Why this answer is correct
The correct answer is A. \(\frac{2}{x^2-1}\). (\frac{1}{x-1}-\frac{1}{x+1}=\frac{x+1-(x-1)}{x-2-1}=\frac{2}{x-2-1}). Watch numerator signs while taking a common denominator.
Exam Tip
(\frac{1}{x-1}-\frac{1}{x+1}=\frac{x+1-(x-1)}{x-2-1}=\frac{2}{x-2-1})। समान हर बनाते समय अंश के चिन्ह देखें।
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