यदि (f(x)=\frac{1}{\sqrt{x}}) और (g(x)=\sqrt{x-1}) हैं, तो (fg) का डोमेन क्या है?

If (f(x)=\frac{1}{\sqrt{x}}) and (g(x)=\sqrt{x-1}), what is the domain of (fg)?

Explanation opens after your attempt
Correct Answer

A. \( [1,\infty\) )

Step 1

Concept

For (f), (x>0), and for (g), \(x\ge1\). Their intersection is \( [1,\infty\) ). For product also, take the common domain of both functions.

Step 2

Why this answer is correct

The correct answer is A. \( [1,\infty\) ). For (f), (x>0), and for (g), \(x\ge1\). Their intersection is \( [1,\infty\) ). For product also, take the common domain of both functions.

Step 3

Exam Tip

(f) के लिए (x>0) और (g) के लिए \(x\ge1\) चाहिए, अतः प्रतिच्छेद \( [1,\infty\) ) है। गुणन में भी दोनों फलनों का साझा डोमेन लें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\frac{1}{\sqrt{x}}) और (g(x)=\sqrt{x-1}) हैं, तो (fg) का डोमेन क्या है? / If (f(x)=\frac{1}{\sqrt{x}}) and (g(x)=\sqrt{x-1}), what is the domain of (fg)?

Correct Answer: A. \( [1,\infty\) ). Explanation: (f) के लिए (x>0) और (g) के लिए \(x\ge1\) चाहिए, अतः प्रतिच्छेद \( [1,\infty\) ) है। गुणन में भी दोनों फलनों का साझा डोमेन लें। / For (f), (x>0), and for (g), \(x\ge1\). Their intersection is \( [1,\infty\) ). For product also, take the common domain of both functions.

Which concept should I revise for this Mathematics MCQ?

For (f), (x>0), and for (g), \(x\ge1\). Their intersection is \( [1,\infty\) ). For product also, take the common domain of both functions.

What exam hint can help solve this Mathematics question?

(f) के लिए (x>0) और (g) के लिए \(x\ge1\) चाहिए, अतः प्रतिच्छेद \( [1,\infty\) ) है। गुणन में भी दोनों फलनों का साझा डोमेन लें।