यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=|x+2|+|x-4|) हो, तो परिसर क्या है?

If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=|x+2|+|x-4|), what is the range?

Explanation opens after your attempt
Correct Answer

A. \([6,\infty\))

Step 1

Concept

For \(-2\le x\le4\), the value is (6), and outside this interval the value increases. Hence the minimum is (6) and the range is \([6,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. \([6,\infty\)). For \(-2\le x\le4\), the value is (6), and outside this interval the value increases. Hence the minimum is (6) and the range is \([6,\infty\)).

Step 3

Exam Tip

\(-2\le x\le4\) पर मान (6) है और बाहर मान बढ़ता है। इसलिए न्यूनतम (6) और परिसर \([6,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=|x+2|+|x-4|) हो, तो परिसर क्या है? / If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=|x+2|+|x-4|), what is the range?

Correct Answer: A. \([6,\infty\)). Explanation: \(-2\le x\le4\) पर मान (6) है और बाहर मान बढ़ता है। इसलिए न्यूनतम (6) और परिसर \([6,\infty\)) है। / For \(-2\le x\le4\), the value is (6), and outside this interval the value increases. Hence the minimum is (6) and the range is \([6,\infty\)).

Which concept should I revise for this Mathematics MCQ?

For \(-2\le x\le4\), the value is (6), and outside this interval the value increases. Hence the minimum is (6) and the range is \([6,\infty\)).

What exam hint can help solve this Mathematics question?

\(-2\le x\le4\) पर मान (6) है और बाहर मान बढ़ता है। इसलिए न्यूनतम (6) और परिसर \([6,\infty\)) है।