यदि \(A={x:x\) \(x^2=4\) का वास्तविक हल है(}) और \(B=\{-2,2\}\) है तो सही कथन क्या है?

If \(A={x:x\) is a real solution of \(x^2=4\)(}) and \(B=\{-2,2\}\) then what is the correct statement?

Explanation opens after your attempt
Correct Answer

A. (A=B)

Step 1

Concept

The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.

Step 2

Why this answer is correct

The correct answer is A. (A=B). The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.

Step 3

Exam Tip

\(x^2=4\) के वास्तविक हल (-2) और (2) दोनों हैं इसलिए (A=B)। परीक्षा में वर्ग समीकरण में ऋणात्मक हल न भूलें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\) \(x^2=4\) का वास्तविक हल है(}) और \(B=\{-2,2\}\) है तो सही कथन क्या है? / If \(A={x:x\) is a real solution of \(x^2=4\)(}) and \(B=\{-2,2\}\) then what is the correct statement?

Correct Answer: A. (A=B). Explanation: \(x^2=4\) के वास्तविक हल (-2) और (2) दोनों हैं इसलिए (A=B)। परीक्षा में वर्ग समीकरण में ऋणात्मक हल न भूलें। / The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.

Which concept should I revise for this Mathematics MCQ?

The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.

What exam hint can help solve this Mathematics question?

\(x^2=4\) के वास्तविक हल (-2) और (2) दोनों हैं इसलिए (A=B)। परीक्षा में वर्ग समीकरण में ऋणात्मक हल न भूलें।