यदि \(A={x:x\) \(x^2=4\) का वास्तविक हल है(}) और \(B=\{-2,2\}\) है तो सही कथन क्या है?
If \(A={x:x\) is a real solution of \(x^2=4\)(}) and \(B=\{-2,2\}\) then what is the correct statement?
Explanation opens after your attempt
A. (A=B)
Concept
The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.
Why this answer is correct
The correct answer is A. (A=B). The real solutions of \(x^2=4\) are both (-2) and (2), so (A=B). In exams do not forget the negative square root.
Exam Tip
\(x^2=4\) के वास्तविक हल (-2) और (2) दोनों हैं इसलिए (A=B)। परीक्षा में वर्ग समीकरण में ऋणात्मक हल न भूलें।
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