यदि \(A={x:x\) संख्या (24) का धनात्मक भाजक है(}), तो (n(\mathcal{P}(A))) क्या होगा?

If \(A={x:x\) is a positive divisor of (24)(}), what is (n(\mathcal{P}(A)))?

Explanation opens after your attempt
Correct Answer

C. (256)

Step 1

Concept

The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).

Step 2

Why this answer is correct

The correct answer is C. (256). The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).

Step 3

Exam Tip

(24) के भाजक (1,2,3,4,6,8,12,24) हैं इसलिए (n(A)=8)। अतः (n(\mathcal{P}(A))=28=256)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\) संख्या (24) का धनात्मक भाजक है(}), तो (n(\mathcal{P}(A))) क्या होगा? / If \(A={x:x\) is a positive divisor of (24)(}), what is (n(\mathcal{P}(A)))?

Correct Answer: C. (256). Explanation: (24) के भाजक (1,2,3,4,6,8,12,24) हैं इसलिए (n(A)=8)। अतः (n(\mathcal{P}(A))=28=256)। / The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).

Which concept should I revise for this Mathematics MCQ?

The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).

What exam hint can help solve this Mathematics question?

(24) के भाजक (1,2,3,4,6,8,12,24) हैं इसलिए (n(A)=8)। अतः (n(\mathcal{P}(A))=28=256)।