यदि \(A={x:x\) संख्या (24) का धनात्मक भाजक है(}), तो (n(\mathcal{P}(A))) क्या होगा?
If \(A={x:x\) is a positive divisor of (24)(}), what is (n(\mathcal{P}(A)))?
Explanation opens after your attempt
C. (256)
Concept
The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).
Why this answer is correct
The correct answer is C. (256). The divisors of (24) are (1,2,3,4,6,8,12,24), so (n(A)=8). Hence (n(\mathcal{P}(A))=28=256).
Exam Tip
(24) के भाजक (1,2,3,4,6,8,12,24) हैं इसलिए (n(A)=8)। अतः (n(\mathcal{P}(A))=28=256)।
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