यदि \(A={x:x\) \(x^2-4=0\) का प्राकृतिक हल है(}) और \(B=\{2\}\) हैं तो कौन सा विकल्प सही है?
If \(A={x:x\) is a natural solution of \(x^2-4=0\)(}) and \(B=\{2\}\), which option is correct?
Explanation opens after your attempt
A. (A=B)
Concept
The equation has roots (-2,2), but the natural solution is only (2). Always check the given number set condition.
Why this answer is correct
The correct answer is A. (A=B). The equation has roots (-2,2), but the natural solution is only (2). Always check the given number set condition.
Exam Tip
समीकरण के हल (-2,2) हैं पर प्राकृतिक हल केवल (2) है। दिए हुए संख्या समुच्चय की शर्त अवश्य देखें।
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