यदि \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) और \(B={x:x\in\mathbb{R},x^2-4x+3=0}\) है, तो \(A\cap B\) क्या है?

If \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) and \(B={x:x\in\mathbb{R},x^2-4x+3=0}\), then what is \(A\cap B\)?

Explanation opens after your attempt
Correct Answer

A. ({3})

Step 1

Concept

The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).

Step 2

Why this answer is correct

The correct answer is A. ({3}). The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).

Step 3

Exam Tip

पहले समीकरण से \(A=\{2,3\}\) और दूसरे से \(B=\{1,3\}\) है। समान तत्व ({3}) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) और \(B={x:x\in\mathbb{R},x^2-4x+3=0}\) है, तो \(A\cap B\) क्या है? / If \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) and \(B={x:x\in\mathbb{R},x^2-4x+3=0}\), then what is \(A\cap B\)?

Correct Answer: A. ({3}). Explanation: पहले समीकरण से \(A=\{2,3\}\) और दूसरे से \(B=\{1,3\}\) है। समान तत्व ({3}) है। / The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).

Which concept should I revise for this Mathematics MCQ?

The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).

What exam hint can help solve this Mathematics question?

पहले समीकरण से \(A=\{2,3\}\) और दूसरे से \(B=\{1,3\}\) है। समान तत्व ({3}) है।