यदि \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) और \(B={x:x\in\mathbb{R},x^2-4x+3=0}\) है, तो \(A\cap B\) क्या है?
If \(A={x:x\in\mathbb{R},x^2-5x+6=0}\) and \(B={x:x\in\mathbb{R},x^2-4x+3=0}\), then what is \(A\cap B\)?
Explanation opens after your attempt
A. ({3})
Concept
The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).
Why this answer is correct
The correct answer is A. ({3}). The first equation gives \(A=\{2,3\}\), and the second gives \(B=\{1,3\}\). The common element is ({3}).
Exam Tip
पहले समीकरण से \(A=\{2,3\}\) और दूसरे से \(B=\{1,3\}\) है। समान तत्व ({3}) है।
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