\(यदि (A={x:x\in \mathbb{N}, x\le 15}) और (B={x:x\in \mathbb{N}, x\) विषम है\(, x\le 15}) है, तो (A-B) क्या है\)?

\(If (A={x:x\in \mathbb{N}, x\le 15}) and (B={x:x\in \mathbb{N}, x\) is odd\(, x\le 15}), what is (A-B)\)?

Explanation opens after your attempt
Correct Answer

B. ( {2,4,6,8,10,12,14} )

Step 1

Concept

(A-B) keeps elements of (A) that are not in (B). So the even numbers up to (15) are the answer.

Step 2

Why this answer is correct

The correct answer is B. ( {2,4,6,8,10,12,14} ). (A-B) keeps elements of (A) that are not in (B). So the even numbers up to (15) are the answer.

Step 3

Exam Tip

(A-B) में (A) के वे अवयव रहेंगे जो (B) में नहीं हैं। इसलिए (15) तक की सम संख्याएं उत्तर हैं।

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Mathematics Answer, Explanation and Revision Hints

\(यदि (A={x:x\in \mathbb{N}, x\le 15}) और (B={x:x\in \mathbb{N}, x\) विषम है, x\le 15}) है, तो (A-B) क्या है? \(/ If (A={x:x\in \mathbb{N}, x\le 15}) and (B={x:x\in \mathbb{N}, x\) is odd\(, x\le 15}), what is (A-B)\)?

Correct Answer: B. ( {2,4,6,8,10,12,14} ). Explanation: (A-B) में (A) के वे अवयव रहेंगे जो (B) में नहीं हैं। इसलिए (15) तक की सम संख्याएं उत्तर हैं। / (A-B) keeps elements of (A) that are not in (B). So the even numbers up to (15) are the answer.

Which concept should I revise for this Mathematics MCQ?

(A-B) keeps elements of (A) that are not in (B). So the even numbers up to (15) are the answer.

What exam hint can help solve this Mathematics question?

(A-B) में (A) के वे अवयव रहेंगे जो (B) में नहीं हैं। इसलिए (15) तक की सम संख्याएं उत्तर हैं।