यदि \(A={x\in\mathbb{R}:x^2\le9}\) और \(B={x\in\mathbb{R}:x^2<1}\), तो (A-B) क्या है?

If \(A={x\in\mathbb{R}:x^2\le9}\) and \(B={x\in\mathbb{R}:x^2<1}\), what is (A-B)?

Explanation opens after your attempt
Correct Answer

A. \([-3,-1]\cup[1,3]\)

Step 1

Concept

(A=[-3,3]) and (B=(-1,1)). Removing (B) gives \([-3,-1]\cup[1,3]\).

Step 2

Why this answer is correct

The correct answer is A. \([-3,-1]\cup[1,3]\). (A=[-3,3]) and (B=(-1,1)). Removing (B) gives \([-3,-1]\cup[1,3]\).

Step 3

Exam Tip

(A=[-3,3]) और (B=(-1,1)) है। (B) हटाने पर \([-3,-1]\cup[1,3]\) मिलता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{R}:x^2\le9}\) और \(B={x\in\mathbb{R}:x^2<1}\), तो (A-B) क्या है? / If \(A={x\in\mathbb{R}:x^2\le9}\) and \(B={x\in\mathbb{R}:x^2<1}\), what is (A-B)?

Correct Answer: A. \([-3,-1]\cup[1,3]\). Explanation: (A=[-3,3]) और (B=(-1,1)) है। (B) हटाने पर \([-3,-1]\cup[1,3]\) मिलता है। / (A=[-3,3]) and (B=(-1,1)). Removing (B) gives \([-3,-1]\cup[1,3]\).

Which concept should I revise for this Mathematics MCQ?

(A=[-3,3]) and (B=(-1,1)). Removing (B) gives \([-3,-1]\cup[1,3]\).

What exam hint can help solve this Mathematics question?

(A=[-3,3]) और (B=(-1,1)) है। (B) हटाने पर \([-3,-1]\cup[1,3]\) मिलता है।