यदि \(A={x\in\mathbb{R}:x^2-5x+6\le0}\) और \(B={x\in\mathbb{R}:x<4}\), तो (A-B) क्या है?
If \(A={x\in\mathbb{R}:x^2-5x+6\le0}\) and \(B={x\in\mathbb{R}:x<4}\), what is (A-B)?
Explanation opens after your attempt
Correct Answer
A. \(\varnothing\)
Concept
\(x^2-5x+6\le0\) gives (A=[2,3]). Every element of (A) lies in (B), so \(A-B=\varnothing\).
Why this answer is correct
The correct answer is A. \(\varnothing\). \(x^2-5x+6\le0\) gives (A=[2,3]). Every element of (A) lies in (B), so \(A-B=\varnothing\).
Exam Tip
\(x^2-5x+6\le0\) से (A=[2,3]) मिलता है। (A) का हर तत्व (B) में है, इसलिए \(A-B=\varnothing\)।
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