यदि \(A={x\in\mathbb{R}:x^2-4x+3>0}\) और \(B={x\in\mathbb{R}:x>1}\), तो \(A\cap B\) क्या है?
If \(A={x\in\mathbb{R}:x^2-4x+3>0}\) and \(B={x\in\mathbb{R}:x>1}\), what is \(A\cap B\)?
Explanation opens after your attempt
Correct Answer
A. (\(3,\infty\))
Concept
\(x^2-4x+3>0\) gives (x<1) or (x>3). With (x>1), the common part is (\(3,\infty\)).
Why this answer is correct
The correct answer is A. (\(3,\infty\)). \(x^2-4x+3>0\) gives (x<1) or (x>3). With (x>1), the common part is (\(3,\infty\)).
Exam Tip
\(x^2-4x+3>0\) से (x<1) या (x>3) मिलता है। (x>1) के साथ सामान्य भाग (\(3,\infty\)) है।
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