यदि \(A={x\in\mathbb{R}:1\le x\le9}\), \(B={x\in\mathbb{R}:3<x<7}\), तो (A-B) क्या है?

If \(A={x\in\mathbb{R}:1\le x\le9}\), \(B={x\in\mathbb{R}:3<x<7}\), what is (A-B)?

Explanation opens after your attempt
Correct Answer

A. \([1,3]\cup[7,9]\)

Step 1

Concept

(B) does not include (3) and (7), so they remain in (A-B). The result is \([1,3]\cup[7,9]\).

Step 2

Why this answer is correct

The correct answer is A. \([1,3]\cup[7,9]\). (B) does not include (3) and (7), so they remain in (A-B). The result is \([1,3]\cup[7,9]\).

Step 3

Exam Tip

(B) में (3) और (7) शामिल नहीं हैं, इसलिए वे (A-B) में रहेंगे। परिणाम \([1,3]\cup[7,9]\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{R}:1\le x\le9}\), \(B={x\in\mathbb{R}:3<x<7}\), तो (A-B) क्या है? / If \(A={x\in\mathbb{R}:1\le x\le9}\), \(B={x\in\mathbb{R}:3<x<7}\), what is (A-B)?

Correct Answer: A. \([1,3]\cup[7,9]\). Explanation: (B) में (3) और (7) शामिल नहीं हैं, इसलिए वे (A-B) में रहेंगे। परिणाम \([1,3]\cup[7,9]\) है। / (B) does not include (3) and (7), so they remain in (A-B). The result is \([1,3]\cup[7,9]\).

Which concept should I revise for this Mathematics MCQ?

(B) does not include (3) and (7), so they remain in (A-B). The result is \([1,3]\cup[7,9]\).

What exam hint can help solve this Mathematics question?

(B) में (3) और (7) शामिल नहीं हैं, इसलिए वे (A-B) में रहेंगे। परिणाम \([1,3]\cup[7,9]\) है।