यदि \(A={x\in\mathbb{N}:x\mid 72}\) और \(B={x\in\mathbb{N}:x\mid 90}\), तो \(A\cap B\) क्या है?

If \(A={x\in\mathbb{N}:x\mid 72}\) and \(B={x\in\mathbb{N}:x\mid 90}\), what is \(A\cap B\)?

Explanation opens after your attempt
Correct Answer

A. ({1,2,3,6,9,18})

Step 1

Concept

Common divisors are divisors of (\gcd(72,90)=18). Thus \(A\cap B={1,2,3,6,9,18}\).

Step 2

Why this answer is correct

The correct answer is A. ({1,2,3,6,9,18}). Common divisors are divisors of (\gcd(72,90)=18). Thus \(A\cap B={1,2,3,6,9,18}\).

Step 3

Exam Tip

सामान्य भाजक (\gcd(72,90)=18) के भाजक होंगे। अतः \(A\cap B={1,2,3,6,9,18}\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{N}:x\mid 72}\) और \(B={x\in\mathbb{N}:x\mid 90}\), तो \(A\cap B\) क्या है? / If \(A={x\in\mathbb{N}:x\mid 72}\) and \(B={x\in\mathbb{N}:x\mid 90}\), what is \(A\cap B\)?

Correct Answer: A. ({1,2,3,6,9,18}). Explanation: सामान्य भाजक (\gcd(72,90)=18) के भाजक होंगे। अतः \(A\cap B={1,2,3,6,9,18}\)। / Common divisors are divisors of (\gcd(72,90)=18). Thus \(A\cap B={1,2,3,6,9,18}\).

Which concept should I revise for this Mathematics MCQ?

Common divisors are divisors of (\gcd(72,90)=18). Thus \(A\cap B={1,2,3,6,9,18}\).

What exam hint can help solve this Mathematics question?

सामान्य भाजक (\gcd(72,90)=18) के भाजक होंगे। अतः \(A\cap B={1,2,3,6,9,18}\)।