यदि \(A={x\in\mathbb{N}: x\le 30,\ 2\mid x}\) और \(B={x\in\mathbb{N}: x\le 30,\ 3\mid x}\), तो \(A\cap B\) क्या है?

If \(A={x\in\mathbb{N}: x\le 30,\ 2\mid x}\) and \(B={x\in\mathbb{N}: x\le 30,\ 3\mid x}\), what is \(A\cap B\)?

Explanation opens after your attempt
Correct Answer

A. ({6,12,18,24,30})

Step 1

Concept

Numbers divisible by both (2) and (3) are divisible by (6). Up to (30), these are ({6,12,18,24,30}).

Step 2

Why this answer is correct

The correct answer is A. ({6,12,18,24,30}). Numbers divisible by both (2) and (3) are divisible by (6). Up to (30), these are ({6,12,18,24,30}).

Step 3

Exam Tip

जो संख्याएं (2) और (3) दोनों से विभाज्य हैं, वे (6) से विभाज्य हैं। (30) तक ऐसी संख्याएं ({6,12,18,24,30}) हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A={x\in\mathbb{N}: x\le 30,\ 2\mid x}\) और \(B={x\in\mathbb{N}: x\le 30,\ 3\mid x}\), तो \(A\cap B\) क्या है? / If \(A={x\in\mathbb{N}: x\le 30,\ 2\mid x}\) and \(B={x\in\mathbb{N}: x\le 30,\ 3\mid x}\), what is \(A\cap B\)?

Correct Answer: A. ({6,12,18,24,30}). Explanation: जो संख्याएं (2) और (3) दोनों से विभाज्य हैं, वे (6) से विभाज्य हैं। (30) तक ऐसी संख्याएं ({6,12,18,24,30}) हैं। / Numbers divisible by both (2) and (3) are divisible by (6). Up to (30), these are ({6,12,18,24,30}).

Which concept should I revise for this Mathematics MCQ?

Numbers divisible by both (2) and (3) are divisible by (6). Up to (30), these are ({6,12,18,24,30}).

What exam hint can help solve this Mathematics question?

जो संख्याएं (2) और (3) दोनों से विभाज्य हैं, वे (6) से विभाज्य हैं। (30) तक ऐसी संख्याएं ({6,12,18,24,30}) हैं।