यदि (A\triangle B=\(A\setminus B\)\cup\(B\setminus A\)) और (|A|=21), (|B|=19), \(|A\cap B|=8\), तो \(|A\triangle B|\) क्या है?
If (A\triangle B=\(A\setminus B\)\cup\(B\setminus A\)) and (|A|=21), (|B|=19), \(|A\cap B|=8\), what is \(|A\triangle B|\)?
Explanation opens after your attempt
Correct Answer
A. (24)
Concept
Here \(|A\triangle B|=|A|+|B|-2|A\cap B|=21+19-16=24\). In symmetric difference, the common part is removed twice.
Why this answer is correct
The correct answer is A. (24). Here \(|A\triangle B|=|A|+|B|-2|A\cap B|=21+19-16=24\). In symmetric difference, the common part is removed twice.
Exam Tip
\(|A\triangle B|=|A|+|B|-2|A\cap B|=21+19-16=24\) है। सममित अंतर में सामान्य भाग दो बार घटता है।
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