यदि \(A=\{p,q,r,s\}\), तो (\mathcal{P}(A)) में (p) नहीं रखने वाले कितने तत्व होंगे?
If \(A=\{p,q,r,s\}\), how many elements of (\mathcal{P}(A)) do not contain (p)?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
Excluding (p), subsets are formed only from (q,r,s), so \(2^3=8\). When one element is forbidden, take the power of the remaining elements.
Why this answer is correct
The correct answer is A. (8). Excluding (p), subsets are formed only from (q,r,s), so \(2^3=8\). When one element is forbidden, take the power of the remaining elements.
Exam Tip
(p) को बाहर रखकर केवल (q,r,s) से उपसमुच्चय बनेंगे, इसलिए \(2^3=8\)। किसी तत्व को हटाने पर शेष तत्वों की शक्ति लें।
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