यदि \(A\cup B=A\triangle B\), जहाँ (A\triangle B=\(A\setminus B\)\cup\(B\setminus A\)), तो कौन सा निष्कर्ष अवश्य सत्य है?
If \(A\cup B=A\triangle B\), where (A\triangle B=\(A\setminus B\)\cup\(B\setminus A\)), which conclusion must be true?
Explanation opens after your attempt
Correct Answer
B. \(A\cap B=\varnothing\)
Concept
The symmetric difference does not include the common part. Therefore it can equal the union only when \(A\cap B=\varnothing\).
Why this answer is correct
The correct answer is B. \(A\cap B=\varnothing\). The symmetric difference does not include the common part. Therefore it can equal the union only when \(A\cap B=\varnothing\).
Exam Tip
सममित अंतर में सामान्य भाग शामिल नहीं होता। इसलिए संघ के बराबर होने के लिए \(A\cap B=\varnothing\) होना चाहिए।
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