यदि \(|A\cup B|=92\), \(|A\setminus B|=31\), और \(|A\cap B|=27\), तो (|B|) कितना है?
If \(|A\cup B|=92\), \(|A\setminus B|=31\), and \(|A\cap B|=27\), what is (|B|)?
Explanation opens after your attempt
Correct Answer
A. (61)
Concept
The union has \(A\setminus B\), \(A\cap B\), and \(B\setminus A\). Here \(B\setminus A=92-31-27=34\), so (|B|=34+27=61).
Why this answer is correct
The correct answer is A. (61). The union has \(A\setminus B\), \(A\cap B\), and \(B\setminus A\). Here \(B\setminus A=92-31-27=34\), so (|B|=34+27=61).
Exam Tip
संघ में \(A\setminus B\), \(A\cap B\) और \(B\setminus A\) हैं। \(B\setminus A=92-31-27=34\), इसलिए (|B|=34+27=61)।
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