यदि (A), (B) और (C) परस्पर असंबद्ध हैं, (n(A)=18), (n(B)=24), (n(C)=29) और (n(U)=90) है, तो (n(\(A\cup B\cup C\)')) कितना है?
If (A), (B) and (C) are mutually disjoint, (n(A)=18), (n(B)=24), (n(C)=29) and (n(U)=90), then what is (n(\(A\cup B\cup C\)'))?
Explanation opens after your attempt
Correct Answer
A. (19)
Concept
For mutually disjoint sets, the union is (18+24+29=71), so the complement is (90-71=19). In disjoint sets, no common part is subtracted.
Why this answer is correct
The correct answer is A. (19). For mutually disjoint sets, the union is (18+24+29=71), so the complement is (90-71=19). In disjoint sets, no common part is subtracted.
Exam Tip
परस्पर असंबद्ध होने पर संघ (18+24+29=71) है, इसलिए पूरक (90-71=19) है। असंबद्ध समुच्चयों में कोई साझा भाग नहीं घटता।
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