यदि \(A=\{a,b,c\}\), \(B=\{1,2\}\) और \(C=\{p,q,r,s\}\) हैं, तो (n(\(A\times B\)\times C)) कितना होगा?

If \(A=\{a,b,c\}\), \(B=\{1,2\}\), and \(C=\{p,q,r,s\}\), what is (n(\(A\times B\)\times C))?

Explanation opens after your attempt
Correct Answer

C. (24)

Step 1

Concept

(n\(A\times B\)=3\cdot2=6) and then \(6\cdot4=24\). An ordered pair is treated as one element in the next Cartesian product.

Step 2

Why this answer is correct

The correct answer is C. (24). (n\(A\times B\)=3\cdot2=6) and then \(6\cdot4=24\). An ordered pair is treated as one element in the next Cartesian product.

Step 3

Exam Tip

(n\(A\times B\)=3\cdot2=6) और फिर \(6\cdot4=24\)। युग्म का तत्व भी अगले कार्तीय गुणन में एक तत्व माना जाता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{a,b,c\}\), \(B=\{1,2\}\) और \(C=\{p,q,r,s\}\) हैं, तो (n(\(A\times B\)\times C)) कितना होगा? / If \(A=\{a,b,c\}\), \(B=\{1,2\}\), and \(C=\{p,q,r,s\}\), what is (n(\(A\times B\)\times C))?

Correct Answer: C. (24). Explanation: (n\(A\times B\)=3\cdot2=6) और फिर \(6\cdot4=24\)। युग्म का तत्व भी अगले कार्तीय गुणन में एक तत्व माना जाता है। / (n\(A\times B\)=3\cdot2=6) and then \(6\cdot4=24\). An ordered pair is treated as one element in the next Cartesian product.

Which concept should I revise for this Mathematics MCQ?

(n\(A\times B\)=3\cdot2=6) and then \(6\cdot4=24\). An ordered pair is treated as one element in the next Cartesian product.

What exam hint can help solve this Mathematics question?

(n\(A\times B\)=3\cdot2=6) और फिर \(6\cdot4=24\)। युग्म का तत्व भी अगले कार्तीय गुणन में एक तत्व माना जाता है।