यदि \(A=\{2,3,4\}\) और \(B=\{6\}\) हैं, तो \(B\times A\) में कितने तत्व होंगे?

If \(A=\{2,3,4\}\) and \(B=\{6\}\), how many elements are in \(B\times A\)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

(n\(B\times A\)=n(B)n(A)=1\times 3=3). Reversing order does not change the count, but it changes the order of pairs.

Step 2

Why this answer is correct

The correct answer is B. (3). (n\(B\times A\)=n(B)n(A)=1\times 3=3). Reversing order does not change the count, but it changes the order of pairs.

Step 3

Exam Tip

(n\(B\times A\)=n(B)n(A)=1\times 3=3)। क्रम बदलने से संख्या नहीं बदलती, पर युग्मों का क्रम बदलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{2,3,4\}\) और \(B=\{6\}\) हैं, तो \(B\times A\) में कितने तत्व होंगे? / If \(A=\{2,3,4\}\) and \(B=\{6\}\), how many elements are in \(B\times A\)?

Correct Answer: B. (3). Explanation: (n\(B\times A\)=n(B)n(A)=1\times 3=3)। क्रम बदलने से संख्या नहीं बदलती, पर युग्मों का क्रम बदलता है। / (n\(B\times A\)=n(B)n(A)=1\times 3=3). Reversing order does not change the count, but it changes the order of pairs.

Which concept should I revise for this Mathematics MCQ?

(n\(B\times A\)=n(B)n(A)=1\times 3=3). Reversing order does not change the count, but it changes the order of pairs.

What exam hint can help solve this Mathematics question?

(n\(B\times A\)=n(B)n(A)=1\times 3=3)। क्रम बदलने से संख्या नहीं बदलती, पर युग्मों का क्रम बदलता है।