यदि \(A=\{1,3\}\) और \(B=\{2,4\}\) हैं, तो \(A\times B\) में दोनों घटकों का योग विषम होने वाले कितने युग्म हैं?
If \(A=\{1,3\}\) and \(B=\{2,4\}\), how many pairs in \(A\times B\) have an odd sum of components?
Explanation opens after your attempt
Correct Answer
C. (4)
Concept
Elements of (A) are odd and elements of (B) are even, so every sum is odd. The total number of pairs is \(2\times 2=4\).
Why this answer is correct
The correct answer is C. (4). Elements of (A) are odd and elements of (B) are even, so every sum is odd. The total number of pairs is \(2\times 2=4\).
Exam Tip
(A) के तत्व विषम और (B) के तत्व सम हैं, इसलिए हर योग विषम होगा। कुल युग्म \(2\times 2=4\) हैं।
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