यदि \(A=\{1,3,5\}\) है, तो (\mathcal{P}(A)) में ऐसे कितने उपसमुच्चय होंगे जिनमें (3) अवश्य हो?
If \(A=\{1,3,5\}\), how many subsets in (\mathcal{P}(A)) must contain (3)?
Explanation opens after your attempt
B. (4)
Concept
Keeping (3) is fixed and the remaining (1,5) may be chosen or not chosen. So the number is \(2^2=4\).
Why this answer is correct
The correct answer is B. (4). Keeping (3) is fixed and the remaining (1,5) may be chosen or not chosen. So the number is \(2^2=4\).
Exam Tip
(3) को रखना निश्चित है और बाकी (1,5) चुने या छोड़े जा सकते हैं। इसलिए संख्या \(2^2=4\) होगी।
Login to save your score, XP, coins and progress.
