यदि \(A=\{1,2\}\), \(B=\{3\}\) और \(C=\{4,5,6\}\) हैं, तो (n\(A\times B\times C\)) कितना होगा?

If \(A=\{1,2\}\), \(B=\{3\}\), and \(C=\{4,5,6\}\), what is (n\(A\times B\times C\))?

Explanation opens after your attempt
Correct Answer

C. (6)

Step 1

Concept

For the product of three sets, the total count is (n(A)n(B)n(C)). Therefore, \(2\times 1\times 3=6\).

Step 2

Why this answer is correct

The correct answer is C. (6). For the product of three sets, the total count is (n(A)n(B)n(C)). Therefore, \(2\times 1\times 3=6\).

Step 3

Exam Tip

तीन समुच्चयों के गुणन में कुल संख्या (n(A)n(B)n(C)) होती है। इसलिए \(2\times 1\times 3=6\)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2\}\), \(B=\{3\}\) और \(C=\{4,5,6\}\) हैं, तो (n\(A\times B\times C\)) कितना होगा? / If \(A=\{1,2\}\), \(B=\{3\}\), and \(C=\{4,5,6\}\), what is (n\(A\times B\times C\))?

Correct Answer: C. (6). Explanation: तीन समुच्चयों के गुणन में कुल संख्या (n(A)n(B)n(C)) होती है। इसलिए \(2\times 1\times 3=6\)। / For the product of three sets, the total count is (n(A)n(B)n(C)). Therefore, \(2\times 1\times 3=6\).

Which concept should I revise for this Mathematics MCQ?

For the product of three sets, the total count is (n(A)n(B)n(C)). Therefore, \(2\times 1\times 3=6\).

What exam hint can help solve this Mathematics question?

तीन समुच्चयों के गुणन में कुल संख्या (n(A)n(B)n(C)) होती है। इसलिए \(2\times 1\times 3=6\)।