यदि \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) और \(C=\{5,7\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे?
If \(A=\{1,2,5\}\), \(B=\{2,3,5\}\) and \(C=\{5,7\}\), how many elements are there in (A\times\(B\cap C\))?
Explanation opens after your attempt
A. (3)
Concept
\(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.
Why this answer is correct
The correct answer is A. (3). \(B\cap C={5}\), so (n(A\times\(B\cap C\))=3\times1=3). First find the intersection and then count the Cartesian product.
Exam Tip
\(B\cap C={5}\), इसलिए (n(A\times\(B\cap C\))=3\times1=3)। पहले प्रतिच्छेद निकालें फिर कार्तीय गुणन गिनें।
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