यदि \(A=\{1,2,3\}\) है, तो (\mathcal{P}(A)) में कितने अरिक्त तत्व होंगे?

If \(A=\{1,2,3\}\), how many non-empty elements are there in (\mathcal{P}(A))?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

Total subsets are \(2^3=8\), and only \(\varnothing\) is empty. So non-empty subsets are (8-1=7).

Step 2

Why this answer is correct

The correct answer is C. (7). Total subsets are \(2^3=8\), and only \(\varnothing\) is empty. So non-empty subsets are (8-1=7).

Step 3

Exam Tip

कुल उपसमुच्चय \(2^3=8\) हैं और केवल \(\varnothing\) रिक्त है। इसलिए अरिक्त उपसमुच्चय (8-1=7) हैं।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3\}\) है, तो (\mathcal{P}(A)) में कितने अरिक्त तत्व होंगे? / If \(A=\{1,2,3\}\), how many non-empty elements are there in (\mathcal{P}(A))?

Correct Answer: C. (7). Explanation: कुल उपसमुच्चय \(2^3=8\) हैं और केवल \(\varnothing\) रिक्त है। इसलिए अरिक्त उपसमुच्चय (8-1=7) हैं। / Total subsets are \(2^3=8\), and only \(\varnothing\) is empty. So non-empty subsets are (8-1=7).

Which concept should I revise for this Mathematics MCQ?

Total subsets are \(2^3=8\), and only \(\varnothing\) is empty. So non-empty subsets are (8-1=7).

What exam hint can help solve this Mathematics question?

कुल उपसमुच्चय \(2^3=8\) हैं और केवल \(\varnothing\) रिक्त है। इसलिए अरिक्त उपसमुच्चय (8-1=7) हैं।