यदि \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\) और \(C=\{4,6,8\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे?

If \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\) and \(C=\{4,6,8\}\), how many elements are in (A\times\(B\cap C\))?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

\(B\cap C={4,6}\), so (n(A\times\(B\cap C\))=4\times2=8). First find the intersection and then multiply.

Step 2

Why this answer is correct

The correct answer is A. (8). \(B\cap C={4,6}\), so (n(A\times\(B\cap C\))=4\times2=8). First find the intersection and then multiply.

Step 3

Exam Tip

\(B\cap C={4,6}\), इसलिए (n(A\times\(B\cap C\))=4\times2=8)। पहले प्रतिच्छेद निकालें फिर गुणन करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\) और \(C=\{4,6,8\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे? / If \(A=\{1,2,3,4\}\), \(B=\{2,4,6\}\) and \(C=\{4,6,8\}\), how many elements are in (A\times\(B\cap C\))?

Correct Answer: A. (8). Explanation: \(B\cap C={4,6}\), इसलिए (n(A\times\(B\cap C\))=4\times2=8)। पहले प्रतिच्छेद निकालें फिर गुणन करें। / \(B\cap C={4,6}\), so (n(A\times\(B\cap C\))=4\times2=8). First find the intersection and then multiply.

Which concept should I revise for this Mathematics MCQ?

\(B\cap C={4,6}\), so (n(A\times\(B\cap C\))=4\times2=8). First find the intersection and then multiply.

What exam hint can help solve this Mathematics question?

\(B\cap C={4,6}\), इसलिए (n(A\times\(B\cap C\))=4\times2=8)। पहले प्रतिच्छेद निकालें फिर गुणन करें।