यदि \(A=\{0,1\}\), \(B=\{2,4\}\) और \(C=\{4,6,8\}\) हैं, तो (A\times\(B\cup C\)) में कितने अवयव होंगे?
If \(A=\{0,1\}\), \(B=\{2,4\}\) and \(C=\{4,6,8\}\), how many elements are in (A\times\(B\cup C\))?
Explanation opens after your attempt
A. (8)
Concept
\(B\cup C={2,4,6,8}\), so (n(A\times\(B\cup C\))=2\times4=8). Do not count common elements twice in a union.
Why this answer is correct
The correct answer is A. (8). \(B\cup C={2,4,6,8}\), so (n(A\times\(B\cup C\))=2\times4=8). Do not count common elements twice in a union.
Exam Tip
\(B\cup C={2,4,6,8}\), इसलिए (n(A\times\(B\cup C\))=2\times4=8)। संघ में समान अवयव को दो बार न गिनें।
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