यदि \(A=\{0,1,2\}\) और \(B=\{2,3\}\) हैं, तो \(A\times B\) में दोनों घटकों का अंतर (1) होने वाले कितने क्रमित युग्म हैं?
If \(A=\{0,1,2\}\) and \(B=\{2,3\}\), how many ordered pairs in \(A\times B\) have the difference of both components equal to (1)?
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Correct Answer
B. (2) युग्म(2) pairs
Concept
The pairs are ((1,2)) and ((2,3)), where the difference between the second and first component is (1). In condition-based questions, first list possible pairs and then check.
Why this answer is correct
The correct answer is B. (2) युग्म / (2) pairs. The pairs are ((1,2)) and ((2,3)), where the difference between the second and first component is (1). In condition-based questions, first list possible pairs and then check.
Exam Tip
ऐसे युग्म ((1,2)) और ((2,3)) हैं, जिनमें दूसरे घटक और पहले घटक का अंतर (1) है। शर्त वाले प्रश्न में पहले संभव युग्म बनाकर जांचें।
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