यदि \(A=\{0,1,2,3\}\) और \(B=\{2,3,4,5\}\) हैं, तो (A-B) और (B-A) के बारे में सही कथन कौन-सा है?

If \(A=\{0,1,2,3\}\) and \(B=\{2,3,4,5\}\), which statement about (A-B) and (B-A) is correct?

Explanation opens after your attempt
Correct Answer

A. (A-B={0,1}) और (B-A={4,5})(A-B={0,1}) and (B-A={4,5})

Step 1

Concept

(0,1) remain in (A-B), and (4,5) remain in (B-A). Set difference is generally not commutative.

Step 2

Why this answer is correct

The correct answer is A. (A-B={0,1}) और (B-A={4,5}) / (A-B={0,1}) and (B-A={4,5}). (0,1) remain in (A-B), and (4,5) remain in (B-A). Set difference is generally not commutative.

Step 3

Exam Tip

(A-B) में (0,1) और (B-A) में (4,5) बचते हैं। समुच्चय अंतर सामान्यतः क्रमविनिमेय नहीं होता।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{0,1,2,3\}\) और \(B=\{2,3,4,5\}\) हैं, तो (A-B) और (B-A) के बारे में सही कथन कौन-सा है? / If \(A=\{0,1,2,3\}\) and \(B=\{2,3,4,5\}\), which statement about (A-B) and (B-A) is correct?

Correct Answer: A. (A-B={0,1}) और (B-A={4,5}) / (A-B={0,1}) and (B-A={4,5}). Explanation: (A-B) में (0,1) और (B-A) में (4,5) बचते हैं। समुच्चय अंतर सामान्यतः क्रमविनिमेय नहीं होता। / (0,1) remain in (A-B), and (4,5) remain in (B-A). Set difference is generally not commutative.

Which concept should I revise for this Mathematics MCQ?

(0,1) remain in (A-B), and (4,5) remain in (B-A). Set difference is generally not commutative.

What exam hint can help solve this Mathematics question?

(A-B) में (0,1) और (B-A) में (4,5) बचते हैं। समुच्चय अंतर सामान्यतः क्रमविनिमेय नहीं होता।