यदि \(A=\{0,1,2,3\}\) और \(B=\{0,1,2,3,4\}\) हैं, तो \(A\times B\) में कितने युग्म ((a,b)) ऐसे हैं जिनमें (a+b<5) है?

If \(A=\{0,1,2,3\}\) and \(B=\{0,1,2,3,4\}\), how many pairs ((a,b)) in \(A\times B\) satisfy (a+b<5)?

Explanation opens after your attempt
Correct Answer

A. (14)

Step 1

Concept

For (a=0,1,2,3), the counts of (b) are (5,4,3,2), totaling (14). In a strict inequality, the boundary is not included.

Step 2

Why this answer is correct

The correct answer is A. (14). For (a=0,1,2,3), the counts of (b) are (5,4,3,2), totaling (14). In a strict inequality, the boundary is not included.

Step 3

Exam Tip

(a=0,1,2,3) के लिए (b) के (5,4,3,2) मान मिलते हैं, कुल (14)। कठोर असमानता में सीमा बराबर नहीं गिनी जाती।

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यदि \(A=\{0,1,2,3\}\) और \(B=\{0,1,2,3,4\}\) हैं, तो \(A\times B\) में कितने युग्म ((a,b)) ऐसे हैं जिनमें (a+b<5) है? / If \(A=\{0,1,2,3\}\) and \(B=\{0,1,2,3,4\}\), how many pairs ((a,b)) in \(A\times B\) satisfy (a+b<5)?

Correct Answer: A. (14). Explanation: (a=0,1,2,3) के लिए (b) के (5,4,3,2) मान मिलते हैं, कुल (14)। कठोर असमानता में सीमा बराबर नहीं गिनी जाती। / For (a=0,1,2,3), the counts of (b) are (5,4,3,2), totaling (14). In a strict inequality, the boundary is not included.

Which concept should I revise for this Mathematics MCQ?

For (a=0,1,2,3), the counts of (b) are (5,4,3,2), totaling (14). In a strict inequality, the boundary is not included.

What exam hint can help solve this Mathematics question?

(a=0,1,2,3) के लिए (b) के (5,4,3,2) मान मिलते हैं, कुल (14)। कठोर असमानता में सीमा बराबर नहीं गिनी जाती।