असमानता \(\frac{5-x}{3}\ge 2\) को संख्या रेखा पर कैसे दिखाएँगे?

How will \(\frac{5-x}{3}\ge 2\) be shown on the number line?

Explanation opens after your attempt
Correct Answer

B. \(x\le -1\), (-1) से बाईं ओर बंद बिंदु\(x\le -1\), closed dot at (-1) shaded left

Step 1

Concept

Solving gives \(5-x\ge 6\), then \(-x\ge 1\), so \(x\le -1\). In exams, remember to reverse the sign when removing (-x).

Step 2

Why this answer is correct

The correct answer is B. \(x\le -1\), (-1) से बाईं ओर बंद बिंदु / \(x\le -1\), closed dot at (-1) shaded left. Solving gives \(5-x\ge 6\), then \(-x\ge 1\), so \(x\le -1\). In exams, remember to reverse the sign when removing (-x).

Step 3

Exam Tip

हल \(5-x\ge 6\) से \(-x\ge 1\) और \(x\le -1\) आता है। परीक्षा में (-x) हटाते समय चिन्ह पलटना न भूलें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{5-x}{3}\ge 2\) को संख्या रेखा पर कैसे दिखाएँगे? / How will \(\frac{5-x}{3}\ge 2\) be shown on the number line?

Correct Answer: B. \(x\le -1\), (-1) से बाईं ओर बंद बिंदु / \(x\le -1\), closed dot at (-1) shaded left. Explanation: हल \(5-x\ge 6\) से \(-x\ge 1\) और \(x\le -1\) आता है। परीक्षा में (-x) हटाते समय चिन्ह पलटना न भूलें। / Solving gives \(5-x\ge 6\), then \(-x\ge 1\), so \(x\le -1\). In exams, remember to reverse the sign when removing (-x).

Which concept should I revise for this Mathematics MCQ?

Solving gives \(5-x\ge 6\), then \(-x\ge 1\), so \(x\le -1\). In exams, remember to reverse the sign when removing (-x).

What exam hint can help solve this Mathematics question?

हल \(5-x\ge 6\) से \(-x\ge 1\) और \(x\le -1\) आता है। परीक्षा में (-x) हटाते समय चिन्ह पलटना न भूलें।