असमानता (3(x-2)\le 2(x+5)) को संख्या रेखा पर कैसे दर्शाएँगे?

How will (3(x-2)\le 2(x+5)) be represented on the number line?

Explanation opens after your attempt
Correct Answer

A. \(x\le 16\), (16) पर बंद बिंदु और बाईं ओर\(x\le 16\), closed dot at (16) shaded left

Step 1

Concept

\(3x-6\le 2x+10\) gives \(x\le 16\). In exams, expand brackets and move like terms carefully.

Step 2

Why this answer is correct

The correct answer is A. \(x\le 16\), (16) पर बंद बिंदु और बाईं ओर / \(x\le 16\), closed dot at (16) shaded left. \(3x-6\le 2x+10\) gives \(x\le 16\). In exams, expand brackets and move like terms carefully.

Step 3

Exam Tip

\(3x-6\le 2x+10\) से \(x\le 16\) मिलता है। परीक्षा में brackets खोलकर like terms को सही side पर रखें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता (3(x-2)\le 2(x+5)) को संख्या रेखा पर कैसे दर्शाएँगे? / How will (3(x-2)\le 2(x+5)) be represented on the number line?

Correct Answer: A. \(x\le 16\), (16) पर बंद बिंदु और बाईं ओर / \(x\le 16\), closed dot at (16) shaded left. Explanation: \(3x-6\le 2x+10\) से \(x\le 16\) मिलता है। परीक्षा में brackets खोलकर like terms को सही side पर रखें। / \(3x-6\le 2x+10\) gives \(x\le 16\). In exams, expand brackets and move like terms carefully.

Which concept should I revise for this Mathematics MCQ?

\(3x-6\le 2x+10\) gives \(x\le 16\). In exams, expand brackets and move like terms carefully.

What exam hint can help solve this Mathematics question?

\(3x-6\le 2x+10\) से \(x\le 16\) मिलता है। परीक्षा में brackets खोलकर like terms को सही side पर रखें।