( \frac{(2n+3)!}{(2n-1)!} ) के विस्तार में कितने गुणक बचते हैं?

How many factors remain in the expansion of ( \frac{(2n+3)!}{(2n-1)!} )?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (4)

Explanation

Simple Explanation

विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं। / The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

FAQs

Mathematics Answer, Explanation and Revision Hints

( \frac{(2n+3)!}{(2n-1)!} ) के विस्तार में कितने गुणक बचते हैं? / How many factors remain in the expansion of ( \frac{(2n+3)!}{(2n-1)!} )?

Correct Answer: B. (4). Explanation: विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं। / The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.