( \frac{(2n+3)!}{(2n-1)!} ) के विस्तार में कितने गुणक बचते हैं?

How many factors remain in the expansion of ( \frac{(2n+3)!}{(2n-1)!} )?

Explanation opens after your attempt
Correct Answer

B. (4)

Step 1

Concept

The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.

Step 2

Why this answer is correct

The correct answer is B. (4). The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.

Step 3

Exam Tip

विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं।

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Mathematics Answer, Explanation and Revision Hints

( \frac{(2n+3)!}{(2n-1)!} ) के विस्तार में कितने गुणक बचते हैं? / How many factors remain in the expansion of ( \frac{(2n+3)!}{(2n-1)!} )?

Correct Answer: B. (4). Explanation: विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं। / The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.

Which concept should I revise for this Mathematics MCQ?

The expansion leaves ((2n+3)(2n+2)(2n+1)(2n)). Therefore there are (4) factors.

What exam hint can help solve this Mathematics question?

विस्तार में ((2n+3)(2n+2)(2n+1)(2n)) बचता है। इसलिए कुल (4) गुणक हैं।