शब्द (CALCULUS) की कितनी भिन्न व्यवस्थाएं बनेंगी?

How many distinct arrangements can be formed from the letters of (CALCULUS)?

Explanation opens after your attempt
Correct Answer

A. (10080)

Step 1

Concept

There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.

Step 2

Why this answer is correct

The correct answer is A. (10080). There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.

Step 3

Exam Tip

(8) अक्षरों में (C,L,U) दो-दो बार हैं, इसलिए संख्या (8!/(2!2!2!)) है। आवृत्तियों को पहचानना मुख्य कदम है।

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शब्द (CALCULUS) की कितनी भिन्न व्यवस्थाएं बनेंगी? / How many distinct arrangements can be formed from the letters of (CALCULUS)?

Correct Answer: A. (10080). Explanation: (8) अक्षरों में (C,L,U) दो-दो बार हैं, इसलिए संख्या (8!/(2!2!2!)) है। आवृत्तियों को पहचानना मुख्य कदम है। / There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.

Which concept should I revise for this Mathematics MCQ?

There are (8) letters with (C,L,U) each repeated twice, so the count is (8!/(2!2!2!)). Identifying repetitions is the key step.

What exam hint can help solve this Mathematics question?

(8) अक्षरों में (C,L,U) दो-दो बार हैं, इसलिए संख्या (8!/(2!2!2!)) है। आवृत्तियों को पहचानना मुख्य कदम है।