शब्द (BALLOON) के अक्षरों की कितनी भिन्न व्यवस्थाएं बनेंगी?
How many distinct arrangements can be formed from the letters of (BALLOON)?
Explanation opens after your attempt
Correct Answer
A. (1260)
Concept
There are (7) letters with (L) and (O) each repeated twice, so the count is (7!/(2!2!)). Repeated letters are not treated as distinct objects.
Why this answer is correct
The correct answer is A. (1260). There are (7) letters with (L) and (O) each repeated twice, so the count is (7!/(2!2!)). Repeated letters are not treated as distinct objects.
Exam Tip
(7) अक्षरों में (L) और (O) दो-दो बार हैं, इसलिए संख्या (7!/(2!2!)) है। समान अक्षर हर बार अलग वस्तु नहीं माने जाते।
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