विस्तार ((n+2)(n+1)n(n-1)(n-2)(n-3)) है। इसलिए (6) लगातार गुणक मिलते हैं। / The expansion is ((n+2)(n+1)n(n-1)(n-2)(n-3)). Therefore there are (6) consecutive factors.
Mathematics Answer, Explanation and Revision Hints
( \frac{(n+2)!}{(n-4)!} ) के विस्तार में कितने लगातार गुणक होंगे? / How many consecutive factors will be in the expansion of ( \frac{(n+2)!}{(n-4)!} )?
Correct Answer: C. (6). Explanation: विस्तार ((n+2)(n+1)n(n-1)(n-2)(n-3)) है। इसलिए (6) लगातार गुणक मिलते हैं। / The expansion is ((n+2)(n+1)n(n-1)(n-2)(n-3)). Therefore there are (6) consecutive factors.
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