अंकों (2,3,4,5,6,7,8) से बिना पुनरावृत्ति कितनी (4)-अंकीय संख्याएं बनेंगी जो (4) से विभाज्य हों?
How many (4)-digit numbers divisible by (4) can be formed from digits (2,3,4,5,6,7,8) without repetition?
Explanation opens after your attempt
A. (90)
Concept
Divisibility by (4) depends on the last two digits; there are (15) valid ordered ending pairs and the first two places fill in \(^{5}P_{2}\) ways. For divisibility by (4), check the last two digits.
Why this answer is correct
The correct answer is A. (90). Divisibility by (4) depends on the last two digits; there are (15) valid ordered ending pairs and the first two places fill in \(^{5}P_{2}\) ways. For divisibility by (4), check the last two digits.
Exam Tip
अंतिम दो अंकों से (4) से विभाज्यता तय होती है; मान्य क्रमित अंतिम जोड़ों की संख्या (15) है और पहले दो स्थान \(^{5}P_{2}\) तरीकों से भरते हैं। (4) से विभाज्यता में अंतिम दो अंक जांचें।
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