व्युत्पत्ति \(^{n}P_r=^{n}C_r r!\) से \(^{n}C_r\) का सही rearranged रूप क्या है?
From the derivation \(^{n}P_r=^{n}C_r r!\), what is the correct rearranged form of \(^{n}C_r\)?
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Correct Answer
B. \(^{n}C_r=\frac{^{n}P_r}{r!}\)
Concept
A permutation includes (r!) orders for each combination. In exams divide ordered count by (r!) to get unordered count.
Why this answer is correct
The correct answer is B. \(^{n}C_r=\frac{^{n}P_r}{r!}\). A permutation includes (r!) orders for each combination. In exams divide ordered count by (r!) to get unordered count.
Exam Tip
Permutation में हर combination के (r!) orders शामिल होते हैं। परीक्षा में unordered count पाने के लिए ordered count को (r!) से divide करें।
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