(8) विद्यार्थियों में से (4) चुनने हैं और दो विशेष विद्यार्थी साथ-साथ नहीं चुने जाने चाहिए। कितने तरीके हैं?
From (8) students, (4) are to be selected and two special students should not be selected together. How many ways are there?
Explanation opens after your attempt
Correct Answer
A. (55)
Concept
Total ways are \(\binom{8}{4}=70\), and ways with both special students are \(\binom{6}{2}=15\). Thus (70-15=55) ways remain.
Why this answer is correct
The correct answer is A. (55). Total ways are \(\binom{8}{4}=70\), and ways with both special students are \(\binom{6}{2}=15\). Thus (70-15=55) ways remain.
Exam Tip
कुल \(\binom{8}{4}=70\) और दोनों विशेष साथ हों तो \(\binom{6}{2}=15\) तरीके हैं। इसलिए (70-15=55) तरीके बचेंगे।
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