(7) विज्ञान और (3) वाणिज्य विद्यार्थियों में से (3) विद्यार्थी चुनने हैं जिनमें ठीक (1) वाणिज्य विद्यार्थी हो। कितने तरीके हैं?

From (7) science and (3) commerce students, (3) students are to be selected with exactly (1) commerce student. How many ways are there?

Explanation opens after your attempt
Correct Answer

A. (63)

Step 1

Concept

For exactly (1) commerce student, the ways are \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\). Use that exact number when exactly is given.

Step 2

Why this answer is correct

The correct answer is A. (63). For exactly (1) commerce student, the ways are \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\). Use that exact number when exactly is given.

Step 3

Exam Tip

ठीक (1) वाणिज्य विद्यार्थी के लिए \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\) तरीके हैं। ठीक शब्द पर वही संख्या लें।

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Mathematics Answer, Explanation and Revision Hints

(7) विज्ञान और (3) वाणिज्य विद्यार्थियों में से (3) विद्यार्थी चुनने हैं जिनमें ठीक (1) वाणिज्य विद्यार्थी हो। कितने तरीके हैं? / From (7) science and (3) commerce students, (3) students are to be selected with exactly (1) commerce student. How many ways are there?

Correct Answer: A. (63). Explanation: ठीक (1) वाणिज्य विद्यार्थी के लिए \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\) तरीके हैं। ठीक शब्द पर वही संख्या लें। / For exactly (1) commerce student, the ways are \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\). Use that exact number when exactly is given.

Which concept should I revise for this Mathematics MCQ?

For exactly (1) commerce student, the ways are \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\). Use that exact number when exactly is given.

What exam hint can help solve this Mathematics question?

ठीक (1) वाणिज्य विद्यार्थी के लिए \(\binom{3}{1}\binom{7}{2}=3\cdot21=63\) तरीके हैं। ठीक शब्द पर वही संख्या लें।