(10) खिलाड़ियों में से (5) चुनने हैं और दो विशेष खिलाड़ी साथ में नहीं चुने जाने चाहिए। कितने तरीके हैं?
From (10) players, (5) are to be selected and two special players should not be selected together. How many ways are there?
Explanation opens after your attempt
Correct Answer
B. (224)
Concept
Total ways are \(\binom{10}{5}=252\), and ways with both special players are \(\binom{8}{3}=56\). Thus the valid ways are (196).
Why this answer is correct
The correct answer is B. (224). Total ways are \(\binom{10}{5}=252\), and ways with both special players are \(\binom{8}{3}=56\). Thus the valid ways are (196).
Exam Tip
कुल \(\binom{10}{5}=252\) और दोनों विशेष साथ हों तो \(\binom{8}{3}=56\) तरीके हैं। इसलिए (252-56=196) नहीं बल्कि सही बचा (196) है।
Login to save your score, XP, coins and progress.